4: You should get
![](gif5/eca5ad2.gif)
Note that once the ln(0) appeared, it was necessary to investigate the zero
closer. Going back to where it started, from n positive one gets that
1 + 1/n > 1, so
ln(1 + 1/n) > 0, that is, it gives a
"positive zero" 0+.
The new limit expression is an
indeterminate ratio, and
since no tricks are apparent, do it the standard way: Use the l'Hospital
rule.
Next hint
Answer