7: Df ) = ℝ; f is continuous there.
y-intercept: f (0) = ln(2); x-intercepts: f = 0 not possible.
f is not symmetric since f (−x) is not equal to f (x) nor to -f (x) (try e.g. x = 1).
Limits at endpoints:

Interpretation as asymptotes:
Horizontal asymptote y = 0 at −∞.
No horizontal asymptote at ∞, but a chance for oblique.

So asymptote y = 3x at ∞.

Now determine monotonicity using f ′.

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Answer