12: After substituting in the limit point you should find that the type is

Although this is an indeterminate ratio, using the l'Hospital rule would not be really wise. Try it and you will see what happens.

Since this is a ratio with powers, it is better to fit this into the box "polynomials and ratios with powers". Using intuitive calculations one can see right away that the "−1" makes no difference for the outcome and it can be ignored. Thus it boils down to the question of which of the powers nn and 2n2 eventually prevails. Unfortunately, the latter is not a part of our basic scale of powers, since the little square in its exponent changes entirely the way it behaves. Thus the scale does not really help, but it is a nice inspiration. If you check out how the comparisons are proved, you will hopefully get some idea how to approach this problem.

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