10: D( f ) = [−2,2];
f is continuous there.
y-intercept: f (0) = 0;
x-intercepts: f = 0
gives x = −2,
x = 0, x = 2.
f (−x) = −f (x),
hence f is odd.
Limits at endpoints:

Interpretation as asymptotes: No asymptotes anywhere.
Now determine monotonicity using f ′.
Next hint
Answer