Tangent and normal lines
There are many ways to determine the equation of a line in the plane. In our
situation we will be looking for an equation of a line that passes through a
certain point (a,b)
and has the slope k. Then the equation reads
y − b = k⋅(x − a).
Since the point lies on the graph of the given function f, we have
b = f (a).
The slope of the line that is tangent to the graph is given by
kT = f ′(a)
so that the line and the curve have the same direction at the touching point. Thus we get the
equation of the tangent line:
y − f (a) = f ′(a)⋅(x − a).
How do we get the normal line? Its direction is perpendicular to the tangent
direction, thus we get its slope using the following fact.
Fact.
Consider two lines in the plane whose slopes are k1 and
k2. These two lines are mutually perpendicular if and only if
k1⋅k2 = −1.
Thus we get the following formula for the slope of the normal line:
Consequently, the equation of the normal line is
For an example see
Tangent line in Methods Survey -
Applications, check out also Solved Problems -
Applications.
Note that the formula
kN = −1/kT
also includes the case when one of these slopes is infinity (a vertical
line) and the other one is zero (horizontal line).
There are many ways in which one can write the equation of a line. Some
people prefer the form
y = A⋅x + B,
others the form
Ax + By = C.
Since all forms are equivalent and it is easy to pass from one to another,
there is no problem to get the form you like. The last form is popular also
because it directly yields a normal vector to the given line, consequently
also a directional vector. These vectors are useful when investigating
geometry. How do we get such vectors?
If we know the slope k of some line, then its directional vector is
B = (1,k). In particular, given a
function f and a point a, then
v = (1,f ′(a)) is the tangent
vector to the graph of f at a. There are two useful special cases:
The tangent vector to an implicit curve
F(x,y) = C can be
also found as
v = (dF/dy,−dF/dx).
The tangent vector to a parametric curve
x = x(t),
y = y(t)
can be also found as
v = (,).
Once we have a tangent vector (u,v), we obtain a
normal vector easily as (v,−u).
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