4: Df ) = (−∞,0) ∪ (0,∞); f is continuous there.
y-intercept: f (0) not possible; x-intercepts: f = 0 not possible.
f is not symmetric since f (−x) is not equal to f (x) nor to -f (x) (try e.g. x = 1).
Limits at endpoints:

Interpretation as asymptotes:
Horizontal asymptote y = 0 at −∞.
Vertical asymptote at x = 0.
No horizontal asymptote at ∞, but a chance for oblique.

So no oblique there.

Now determine monotonicity using f ′.

Next hint
Answer