11: This integral does not fit any box. There are two distinct roots, so substitution would not help. Integration by parts does not seem possible, so we are left with algebraic tricks. There are two possible approaches (actually three). On one hand, one can pick one of the two roots and divide both the numerator and the denominator, obtaining just one expression in the function. On the other hand, one can also try to rationalize the denominator, hoping that the numerator will then be nice.