14: The condition that the point lies on the hyperbola reads
y2 = x2/2 − 1,
this allows one to get rid of y. Moreover, optimizing a positive
function is equivalent to optimizing its square, which allows for another
simplification.
The function
should be minimized over the set M of real numbers
(the point can be anywhere, there is no natural restriction on x).
Use the appropriate
algorithm.
